HVAC & Energy
Air Cooling Load Calculator
Calculate sensible and latent cooling from an entered moist-air process or reverse airflow. Compare SI/US results and review the method, assumptions and related references below.
Change any input to update the calculation. Unit changes preserve the physical quantity.
Inputs
Mass of vapor per mass of dry air, not relative humidity percent.
Calculated locally in your browser. No sign-up or input upload.
Results
Total air-process cooling
19.9639 kW68,119.5918 BTU/hSensible cooling
10.9921 kW37,506.7454 BTU/hLatent remainder
8.9717 kW30,612.8464 BTU/hSensible heat ratio
0.5506Volume flow
500 L/s30,000 L/min1,800 m³/h7,925.1616 GPM (US)1,059.44 CFMIdeal condensed moisture
12.7811 kg/hEntering enthalpy
68.0393 kJ/kg dry airLeaving enthalpy
34.3003 kJ/kg dry airCalculation breakdown
- Result interpretation
- Calculate sensible and latent cooling from an entered moist-air process or reverse airflow
Assumptions & checks
Entered air-process estimate, not building cooling load or equipment selection. Model range 0–60°C; supersaturated states rejected. Condensate sensible enthalpy and coil bypass are excluded.
Formula
Calculate sensible and latent cooling from an entered moist-air process or reverse airflow
Worked example
Using the default values shown in the calculator, the same formula gives the following result. This is a quick sanity check for the calculation, not a design recommendation.
Inputs
- Entering air volume flow
- 500 L/s
- Entering air temperature
- 32 °C
- Leaving air temperature
- 14 °C
- Entering humidity ratio
- 14 g/kg dry air
- Leaving humidity ratio
- 8 g/kg dry air
- Entering moist-air density
- 1.2 kg/m³
- Atmospheric pressure
- 101.325 kPa
Result
- Total air-process cooling
- 19.9639 kW
- Sensible cooling
- 10.9921 kW
- Latent remainder
- 8.9717 kW
- Sensible heat ratio
- 0.5506
- Volume flow
- 500 L/s
- Ideal condensed moisture
- 12.7811 kg/h
- Entering enthalpy
- 68.0393 kJ/kg dry air
- Leaving enthalpy
- 34.3003 kJ/kg dry air
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Technical references for this calculation
Frequently asked questions
What does this result tell me?
Entered air-process estimate, not building cooling load or equipment selection. Model range 0–60°C; supersaturated states rejected. Condensate sensible enthalpy and coil bypass are excluded.
How can I check the calculation?
Worked example: 500 L/s, 1.2 kg/m³, 32°C/14 g/kg entering and 14°C/8 g/kg leaving gives approximately 20.20 kW and 12.78 kg/h condensate. Review each stated input and unit; use project-specific values rather than treating the editable example as a requirement.
Reference data & method sources
- ASHRAE psychrometrics
Ideal moist-air enthalpy and saturation over liquid water; humidities are per kilogram of dry air.
- NIST SI conversion factors
SI/US dimensional conversions. Geometry and energy balances are stated explicitly, not attributed to a design standard.